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          leetcode的SQL入门题
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            <div class="post-description">简介：leetcode的SQL入门题</div>
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        <p>题集如下：<br><a target="_blank" rel="noopener" href="https://leetcode-cn.com/study-plan/sql/">https://leetcode-cn.com/study-plan/sql/</a></p>
<h1 id="第一天：选择"><a href="#第一天：选择" class="headerlink" title="第一天：选择"></a>第一天：选择</h1><h2 id="595-大的国家"><a href="#595-大的国家" class="headerlink" title="595.大的国家"></a>595.大的国家</h2><p><a target="_blank" rel="noopener" href="https://leetcode-cn.com/problems/big-countries/">https://leetcode-cn.com/problems/big-countries/</a></p>
<p>我的题解：</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br></pre></td><td class="code"><pre><span class="line"># Write your MySQL query statement below</span><br><span class="line">select name,population,area from World</span><br><span class="line">where area&gt;=3000000 or population&gt;=25000000</span><br></pre></td></tr></table></figure>



<p>结果：</p>
<p><strong>5 / 5</strong> 个通过测试用例<br>状态：<em>通过</em><br>执行用时: <strong>198 ms</strong><br>内存消耗: <strong>0 B</strong></p>
<h2 id="1757-可回收且低脂的产品"><a href="#1757-可回收且低脂的产品" class="headerlink" title="1757. 可回收且低脂的产品"></a>1757. 可回收且低脂的产品</h2><p><a target="_blank" rel="noopener" href="https://leetcode-cn.com/problems/recyclable-and-low-fat-products/">https://leetcode-cn.com/problems/recyclable-and-low-fat-products/</a></p>
<p>我的题解：</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br></pre></td><td class="code"><pre><span class="line"># Write your MySQL query statement below</span><br><span class="line">select product_id from Products where low_fats = &#x27;Y&#x27; and recyclable = &#x27;Y&#x27;</span><br></pre></td></tr></table></figure>

<p>结果：<br>执行结果：<br>通过</p>
<p>执行用时：620 ms<br>, 在所有 MySQL 提交中击败了19.46%的用户</p>
<p>内存消耗：0 B<br>, 在所有 MySQL 提交中击败了100.00%的用户</p>
<p>通过测试用例：<br>22 / 22</p>
<h2 id="584-寻找用户推荐人"><a href="#584-寻找用户推荐人" class="headerlink" title="584. 寻找用户推荐人"></a>584. 寻找用户推荐人</h2><p><a target="_blank" rel="noopener" href="https://leetcode-cn.com/problems/find-customer-referee/">https://leetcode-cn.com/problems/find-customer-referee/</a></p>
<p>我的题解：</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br></pre></td><td class="code"><pre><span class="line"># Write your MySQL query statement below</span><br><span class="line">select name from customer</span><br><span class="line">where referee_id != 2 or referee_id is NULL</span><br></pre></td></tr></table></figure>





<p>执行结果：</p>
<p>通过</p>
<p>显示详情</p>
<p>执行用时：474 ms, 在所有 MySQL 提交中击败了84.25%的用户</p>
<p>内存消耗：0 B, 在所有 MySQL 提交中击败了100.00%的用户</p>
<p>通过测试用例：19 / 19</p>
<h2 id="183-从不订购的客户"><a href="#183-从不订购的客户" class="headerlink" title="183. 从不订购的客户"></a>183. 从不订购的客户</h2><p><a target="_blank" rel="noopener" href="https://leetcode-cn.com/problems/customers-who-never-order/">https://leetcode-cn.com/problems/customers-who-never-order/</a></p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br></pre></td><td class="code"><pre><span class="line"># Write your MySQL query statement below</span><br><span class="line">select Customers.Name as Customers from Customers</span><br><span class="line">where Customers.Id not in (select CustomerId from Orders)</span><br></pre></td></tr></table></figure>



<p>执行结果：</p>
<p>通过</p>
<p>显示详情</p>
<p>执行用时：540 ms, 在所有 MySQL 提交中击败了70.44%的用户</p>
<p>内存消耗：0 B, 在所有 MySQL 提交中击败了100.00%的用户</p>
<p>通过测试用例：11 / 11</p>
<h1 id="第二天-排序-amp-修改"><a href="#第二天-排序-amp-修改" class="headerlink" title="第二天 排序 &amp; 修改"></a>第二天 排序 &amp; 修改</h1><h2 id="1873-计算特殊奖金"><a href="#1873-计算特殊奖金" class="headerlink" title="1873. 计算特殊奖金"></a>1873. 计算特殊奖金</h2><p><a target="_blank" rel="noopener" href="https://leetcode-cn.com/problems/calculate-special-bonus/">https://leetcode-cn.com/problems/calculate-special-bonus/</a></p>
<p>方法一、UNION + NOT LIKE</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br></pre></td><td class="code"><pre><span class="line">SELECT employee_id ,salary AS bonus</span><br><span class="line">FROM Employees</span><br><span class="line">WHERE employee_id%2!=0 AND name NOT LIKE (&#x27;M%&#x27;)</span><br><span class="line">UNION </span><br><span class="line">SELECT employee_id ,salary*0 AS bonus</span><br><span class="line">FROM Employees</span><br><span class="line">WHERE employee_id%2=0 OR name LIKE (&#x27;M%&#x27;)</span><br><span class="line">ORDER BY employee_id;</span><br></pre></td></tr></table></figure>


<p>方法二、IF +RIGHT +MOD</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br></pre></td><td class="code"><pre><span class="line">SELECT employee_id,</span><br><span class="line">IF(MOD(employee_id,2)!=0 AND LEFT(name,1)!=&#x27;M&#x27;,salary,0) bonus</span><br><span class="line">FROM Employees</span><br><span class="line">ORDER BY employee_id</span><br></pre></td></tr></table></figure>


<p>方法三、CASE+RIGHT +MOD</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br></pre></td><td class="code"><pre><span class="line">SELECT employee_id,</span><br><span class="line">(CASE WHEN MOD(employee_id,2)!=0 AND LEFT(name,1)!=&#x27;M&#x27; THEN salary</span><br><span class="line">     WHEN MOD(employee_id,2)=0 OR LEFT(name,1)=&#x27;M&#x27; THEN 0</span><br><span class="line">END) bonus</span><br><span class="line">FROM Employees</span><br><span class="line">ORDER BY employee_id</span><br></pre></td></tr></table></figure>


<p>方法四、CASE WHEN THEN</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br></pre></td><td class="code"><pre><span class="line">SELECT employee_id,</span><br><span class="line">    (CASE WHEN MOD(employee_id,2)!=0 AND name NOT LIKE &#x27;M%&#x27; THEN salary ELSE 0 END) AS bonus</span><br><span class="line">FROM Employees</span><br></pre></td></tr></table></figure>

<p>CASE的教程：<a target="_blank" rel="noopener" href="https://www.bilibili.com/video/BV1Cu411Z74k/">https://www.bilibili.com/video/BV1Cu411Z74k/</a></p>
<h2 id="627-变更性别"><a href="#627-变更性别" class="headerlink" title="627. 变更性别"></a>627. 变更性别</h2><p><a target="_blank" rel="noopener" href="https://leetcode-cn.com/problems/swap-salary/">https://leetcode-cn.com/problems/swap-salary/</a></p>
<p>方法一、CASE WHEN THEN</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br></pre></td><td class="code"><pre><span class="line">update salary</span><br><span class="line">set sex = (</span><br><span class="line">    case sex when &#x27;m&#x27; then &#x27;f&#x27; else &#x27;m&#x27; end</span><br><span class="line">);</span><br></pre></td></tr></table></figure>


<p>方法二、if</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br></pre></td><td class="code"><pre><span class="line">update salary set sex = if(sex = &#x27;m&#x27;,&#x27;f&#x27;,&#x27;m&#x27;)</span><br></pre></td></tr></table></figure>


<p>方法三、ASCII码</p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br></pre></td><td class="code"><pre><span class="line">update salary set sex = char(ascii(&#x27;m&#x27;) + ascii(&#x27;f&#x27;) - ascii(sex));</span><br></pre></td></tr></table></figure>



<h2 id="196-删除重复的电子邮箱"><a href="#196-删除重复的电子邮箱" class="headerlink" title="196. 删除重复的电子邮箱"></a>196. 删除重复的电子邮箱</h2><p><a target="_blank" rel="noopener" href="https://leetcode-cn.com/problems/delete-duplicate-emails/">https://leetcode-cn.com/problems/delete-duplicate-emails/</a></p>
<figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br></pre></td><td class="code"><pre><span class="line">delete u</span><br><span class="line">from Person u , Person v</span><br><span class="line">where v.id &lt; u.id and u.email = v.email </span><br></pre></td></tr></table></figure>


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